Respuesta :

sushantpandey238

3x-y=2....(i)

2x-y=3.....(ii)

now adding the eqn I and ii ,

3x-y=2

2x-y=3

+ + +

5x=5

x=1

Now substituting the value of x in eqn I

3×1-y=2

3-y=2

-y=-1

y=1