Respuesta :

In 0.190 mole of C6H14O, there is 0.190*6 (number of C in one molecule) = 1.140 mole of C atoms. The total number of C atoms = 1.14 * 6*[tex] 10^{23} [/tex] (atoms of C in one mole) = 6.84*[tex] 10^{23} [/tex] atoms. 

Otras preguntas